Send another e-mail to your blog called “Corrections to…” and highlight the changes in a different colour.Dear 11.1X,Here are the answers to the questions as promised. Now correct the work that you blogged. Two options to do this:1.
2. Edit your blog post and make the changes in a different colour.
Cheers,Mr B5.9 and 5.10 answers28 October 201110:215.7 and 5.8 Starter answers28 October 201111:00· What are the 6 processes shown by the arrows?
Melting
Boiling
5.7 and 5.8 Answers28 October 201110:20· Collins p.1121a
· Particles in a solid are strongly bonded to each other so their particles are held in a fixed, regular pattern and can not move· The bonds between particles in liquids and gases are weaker and therefore their particles can move relative to each other
1b
· The particles in solids and liquids are closely packed and they are therefore incompressible· The particles in a gas are very widely spaced and the forces between them are very weak so they can spread out to fill their containerBoiling
· Boiling occurs when you heat a liquid until the average energy of the particles is great enough for them to turn into a gas· Boiling occurs at a fixed temperature called the boiling point· Boiling occurs throughout a liquid· It is a fast process·
Evaporation
· Evaporation occurs when a liquid is left open to the air· Only particles at the surface of the liquid that have enough energy can escape the liquid into the air· Evaporation occurs for a range of temperatures; high temperatures increase evaporation, low temperatures decrease evaporation· Evaporation only occurs from the surface of a liquid· It is a slower process· Because it removes the most energetic particles from a liquid the average energy of the remaining particles is decreased and the liquid cools down·
Friday, 28 October 2011
Answers
5.7 and 5.8
5.7 and 5.8 Starter. Find out the names of the processes. Research on the internet if necessary. No need to blog this.Dear 11.1X,Instructions for Objective 5.7 and 5.81.
2. 5.7 and 5.8. Forward this e-mail to your blog and type the answers into the e-mail.
3. 5.7 and 5.8 Experiment. I’m afraid you can’t do the expt until we get back but watch the video clip to see how it’s set up and have a look at the graph of the results.
4. 5.7 to 5.10 Plenary 1. Play the attached “States of Matter”
5. 5.7 to 5.10 Plenary 2. Play the attached “Fill the trucks”
6. PhET States of matter simulation - embedding into your Posterous blog. Embed in your blog and then have a play
5.7 and 5.8 Starter28 October 201111:00· What are the 6 processes shown by the arrows?
5.7 and 5.828 October 201110:20·5.7 understand that a substance can change state from solid to liquid by the process of melting· 5.8 understand that a substance can change state from liquid to gas by the process of evaporation or boiling· Questions from Collins p.112· Answer in Bullet Points!
Q1
·Use following pages from Collins as a resource to help you
5.7 and 5.8 Experiment - Cooling Curve of Stearic Acid using datalogger15 October 201014:34
5.7 to 5.10 Plenary 128 October 201112:19
·Play the Stage 1 game to test your knowledge of solids, liquids and gases· Play the Stage 2 game to test your knowledge about changes of phase!
5.7 to 5.10 Plenary 228 October 201112:19
Play the Level 1 game to test your knowledge of the properties of solids, liquids and gases
Extension: Play the Level 2 game to extend your knowledge about changes of phase!PhET States of matter simulation - embedding into your Posterous blog28 October 201111:14· Create a post
·Turn on HTML editor
[[posterous-content:BxcAiJvlRwQJUn
5.9 and 5.10 starter
5.9 and 5.10 Starter. Think through your answers and then verify with the attached animationDear 11.1X,This e-lesson consists of 4 objectives; 5.7 to 5.10. I’ll e-mail the other two objectives separately.Instructions for Objective 5.9 and 5.101.
2. 5.9 and 5.10. Forward this e-mail to your blog and complete the table
3. Answers to step 2 will be sent separately. Don’t look at them until you’ve done the work!
Best wishes,Mr B5.9 and 5.10 starter28 October 201112:01Tell the person next to you…
· How do particles in move in a solid, a liquid and a gas?· Describe…o speed of particleso relative position of particles (fixed or not)o pattern of particles (regularly arranged or not)o size of the particleso space between the particleso strength of bonds between the particles
Use the animation to verify your answers
5.9 and 5.1028 October 201110:21· 5.9 recall that particles in a liquid have a random motion within a close-packed irregular structure· 5.10 recall that particles in a solid vibrate about fixed positions within a close-packed regular structure· Complete the missing words in the table below· Cut and paste the particle images into the table
State ParticlePicture Arrangement of Particles Motion of Particles Other Properties Solid ·closely packed· regular pattern · vibrate about a fixed position · fixed shape· not easily compressed since particles are closely packed· Strong bonds Liquid · closely packed· no pattern · free to flow over each other · takes shape of its container· can be p_____d· not easily compressed since particles are closely packed· Weak bonds Gas · widely spaced· no pattern · very fast m____g· random directions ·  
Wednesday, 12 October 2011
5.6 Questions
5.6 Questions
07 October 2011 11:53 Collins, p.107 [cid:image001.jpg@01CC88F0.11386960] Note: ρfresh water = 1,000kg/m3; g = 10N/kg ps. 1,000mbar = 1 bar = 100,000Pa! ANSWERS Collins, p107 Q5 pressure difference = height × density × g ∆p = h × ρ × g ∆p = pressure of the fluid (N/m2 or Pa) = 250kPa - 100kPa = 150kPa (x1000) = 150 000 h = height FROM SURFACE LEVEL (m) = ? ρ = density of the fluid (kg/m3) = 1000 g = gravitational field strength (N/kg) = 10 height => h = 150 000/ (1000 x 10) = 15m OR NOTE IN FRESH WATER: EVERY 10m descend = +100kPaIf he was diving in water that was slightly denser than fresh water then we see from the equation that the pressure difference would be divided by a greater number, therefore the answer would be less meaning that the diver would dive less below the surface. Q6 pressure difference = height × density × g ∆p = h × ρ × g ∆p = pressure of the fluid (N/m2 or Pa) = ? h = height FROM SURFACE LEVEL (m) = 50 ρ = density of the fluid (kg/m3) = 0.42g/cm3 = 0.00042kg/cm3 => (1cm3 = 1/100^3) = 0.00042 x 100^3 = 420 OR NOTE: 1 g/cm3 = 1000kg/m3 g = gravitational field strength (N/kg) = 1.4 NOTE: 1 g/cm3 = 1000kg/m3 ∆p =50 x 420 x 1.4 = 29400Pa OR 29.4kPa Total pressure (atmospheric pressure on Titan = 1600mbar (1 mbar = 0.1kPa = 100Pa) => 1600 x 0.1 = 160kPa TP = 160 +29.4 = 189.4kPa
5.6 Demo - squirting water column
[cid:image001.jpg@01CC88EF.74EC5B70]
· The bottom hole squirts water the furthest
· Because the water at the bottom has the greatest pressure
· Because in the formula ∆p = h × ρ × g, ρ is constant, g is constant and h is large
· So ∆p = large
5.6
5.5
5.5 Demo 1 - Magdeburg Hemispheres
5.5 Demo 1 - Magdeburg Hemispheres
12 October 2011 07:19· Magdeburg Hemispheres [cid:image001.jpg@01CC88ED.8C0B76D0]
· And here are the horses I was talking about! http://www.youtube.com/watch?v=7bJkaFByiA0&feature=related
5.4 Model answers to Written questions
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[cid:image003.png@01CC88E3.AA03EF00]
4.17 Answers
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5.4
· 5.4 recall and use the relationship between pressure, force and area:
pressure = force / area p = F / A5.4 Harder questions on Pressure
5.4 Harder questions on Pressure
07 October 2011 16:30· Collins, p.107, Q.4. [cid:image001.png@01CC88E3.D010D6E0] ANSWER Shoe heel: p = F / A p = 400 / (0.05 x 0.05) p = 160 000N / m2 Elephant: p = F / A p = 5000 / (pi x 0.1^2) p = 159 155 N / cm2 High-heel shoe: p = F / A p = 400 / (1/20000) p = 8 000 000 N / m2 Which ones will damage a floor that yields at a pressure of 4000 kPa?
High - heel shoe ONLY
5.4 Starter
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Tuesday, 11 October 2011
5.2 Harder Questions
· Collins p.106 Q.1-3. (Table of densities below) [cid:image001.png@01CC84CD.0F0A7F10] [cid:image002.jpg@01CC84CD.0F0A7F10]
[cid:image003.jpg@01CC84CD.0F0A7F10] ANSWERS Q1 Wood in Oil = Float
Wood in Mercury = Float
Plastic in Oil = Sink
Steel in Mercury = Float
Silver in Air = Sink
Gold in Mercury (this experiment must be done rapidly as the gold will dissolve quickly) = Sink
Helium balloon = Float Q2 Dimensions: 0.200 x 0.090 x 0.065 (0.065 = 3.d.p.) Mass of brick => m = W/g = 22.2/10 = 2.2kg Volume of Brick => V = 0.200 x 0.090 x 0.065 = 0.00126 Density of Brick => p = mass / volume = 2.2/0.00126 = 1746.031..... = 1746 kg/m^3 Q3 (1.93kg = 1930g) volume of crown = mass / density => 1930 / 19.3 = 100cm3 new water level = 800 + 100 = 900cm3 (if pure gold) IF not pure gold, the water level will be different because density affects the volume displaced (v = m/p)
Thursday, 6 October 2011
Density of a Liquid
m(cylinder + liquid) = 85g
m(liquid) = m(cylinder + liquid) - m(cylinder) = 85 - 61 = 24g
V = 25cm^3 = 25ml
p = m / V = 24 / 25 = 0.96 g / cm^3 Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
5.3
· 5.3 describe how to determine density using direct measurements of mass and volume
Density of an Irregular Object
V = 32g
p = m / V = 45 / 32 = 1.4g Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
5.3 Plenary 2
· How can you make a cannonball float? Explanation below… Density of Mercury = 7.9g/cm3 or 7,900kg/m3 Density of Iron = 13.6g/cm3 or 13,600kg/m3 NOTE LESS DENSITY = FLOATS MORE (E.G. OIL LESS DENSE THEREFORE FLOATS ON TOP OF WATER)
ALTERATIONS
p = 3.82 / (0.7 x 0.7 x 3.9)
p = 1.9989...
p = 2.00 g /cm^3 PFY p120 (september 21 2011) Questions (see screenshot) Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
Untitled
p = 3.82 / (0.7 x 0.7 x 3.9) p = 1.9989... p = 2.00 g /cm^3 PFY p120 (september 21 2011) Questions (see screenshot) Kavin (Nik) Supatravanij
Bangkok Patana School, 11B