*** PREVIOUS TOPIC 4.17 Answers 07 September 2011 14:45 > Inserted from: >
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Wednesday, 12 October 2011
5.4
· 5.4 recall and use the relationship between pressure, force and area:
pressure = force / area p = F / A5.4 Harder questions on Pressure
5.4 Harder questions on Pressure
07 October 2011 16:30· Collins, p.107, Q.4. [cid:image001.png@01CC88E3.D010D6E0] ANSWER Shoe heel: p = F / A p = 400 / (0.05 x 0.05) p = 160 000N / m2 Elephant: p = F / A p = 5000 / (pi x 0.1^2) p = 159 155 N / cm2 High-heel shoe: p = F / A p = 400 / (1/20000) p = 8 000 000 N / m2 Which ones will damage a floor that yields at a pressure of 4000 kPa?
High - heel shoe ONLY
5.4 Starter
5.4 Starter 07 October 2011 11:46 >
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Tuesday, 11 October 2011
5.2 Harder Questions
5.2 Harder Questions 07 October 2011 07:46
· Collins p.106 Q.1-3. (Table of densities below) [cid:image001.png@01CC84CD.0F0A7F10] [cid:image002.jpg@01CC84CD.0F0A7F10]
[cid:image003.jpg@01CC84CD.0F0A7F10] ANSWERS Q1 Wood in Oil = Float
Wood in Mercury = Float
Plastic in Oil = Sink
Steel in Mercury = Float
Silver in Air = Sink
Gold in Mercury (this experiment must be done rapidly as the gold will dissolve quickly) = Sink
Helium balloon = Float Q2 Dimensions: 0.200 x 0.090 x 0.065 (0.065 = 3.d.p.) Mass of brick => m = W/g = 22.2/10 = 2.2kg Volume of Brick => V = 0.200 x 0.090 x 0.065 = 0.00126 Density of Brick => p = mass / volume = 2.2/0.00126 = 1746.031..... = 1746 kg/m^3 Q3 (1.93kg = 1930g) volume of crown = mass / density => 1930 / 19.3 = 100cm3 new water level = 800 + 100 = 900cm3 (if pure gold) IF not pure gold, the water level will be different because density affects the volume displaced (v = m/p) 
· Collins p.106 Q.1-3. (Table of densities below) [cid:image001.png@01CC84CD.0F0A7F10] [cid:image002.jpg@01CC84CD.0F0A7F10]
[cid:image003.jpg@01CC84CD.0F0A7F10] ANSWERS Q1 Wood in Oil = Float
Wood in Mercury = Float
Plastic in Oil = Sink
Steel in Mercury = Float
Silver in Air = Sink
Gold in Mercury (this experiment must be done rapidly as the gold will dissolve quickly) = Sink
Helium balloon = Float Q2 Dimensions: 0.200 x 0.090 x 0.065 (0.065 = 3.d.p.) Mass of brick => m = W/g = 22.2/10 = 2.2kg Volume of Brick => V = 0.200 x 0.090 x 0.065 = 0.00126 Density of Brick => p = mass / volume = 2.2/0.00126 = 1746.031..... = 1746 kg/m^3 Q3 (1.93kg = 1930g) volume of crown = mass / density => 1930 / 19.3 = 100cm3 new water level = 800 + 100 = 900cm3 (if pure gold) IF not pure gold, the water level will be different because density affects the volume displaced (v = m/p)
Thursday, 6 October 2011
Density of a Liquid
ANSWERS m(cylinder) = 61g
m(cylinder + liquid) = 85g
m(liquid) = m(cylinder + liquid) - m(cylinder) = 85 - 61 = 24g
V = 25cm^3 = 25ml
p = m / V = 24 / 25 = 0.96 g / cm^3 Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
m(cylinder + liquid) = 85g
m(liquid) = m(cylinder + liquid) - m(cylinder) = 85 - 61 = 24g
V = 25cm^3 = 25ml
p = m / V = 24 / 25 = 0.96 g / cm^3 Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
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