Density starter - Moon Rock.ppt Download this file
Thursday, 6 October 2011
ALTERATIONS
5.3 PRACTICAL p = m / V
p = 3.82 / (0.7 x 0.7 x 3.9)
p = 1.9989...
p = 2.00 g /cm^3 PFY p120 (september 21 2011) Questions (see screenshot) Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
p = 3.82 / (0.7 x 0.7 x 3.9)
p = 1.9989...
p = 2.00 g /cm^3 PFY p120 (september 21 2011) Questions (see screenshot) Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
Untitled
ALTERATIONS 5.3 PRACTICAL p = m / V
p = 3.82 / (0.7 x 0.7 x 3.9) p = 1.9989... p = 2.00 g /cm^3 PFY p120 (september 21 2011) Questions (see screenshot) Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
p = 3.82 / (0.7 x 0.7 x 3.9) p = 1.9989... p = 2.00 g /cm^3 PFY p120 (september 21 2011) Questions (see screenshot) Kavin (Nik) Supatravanij
Bangkok Patana School, 11B
P5 Keywords - First Homework
Unit 5 Keywords and Mixed Definitions.doc Download this file
P5 Keywords - First Homework
02 September 2010 18:41 Step 1 = Unscramble the Keywords and Mixed Definitions sheet. 4 options:· Kinaesthetic Learners = Cut and Stick into your exercise book. Take a photo of your work and send to your blog.
· Kinaesthetic Learners = Cut and Paste in the Word document and send to your blog
· Visual Learners = Copy out into your exercise book. Take a photo of your work and send to your blog.
· Visual Learners = Type out and send to your blog Step 2 = Check your keywords by using one of the following online games. Mark each keyword with a red pen. Correct any mistakes and re-send to your blog.
· http://www.patana.ac.th/LearningObjects/%7BA402677E-6AED-40AC-B74F-36F16A1B7B...
· http://www.patana.ac.th/LearningObjects/%7B9D263F53-58C9-44D0-BC0E-1CA4E2B1E9...
· http://www.patana.ac.th/LearningObjects/%7BC1B28B63-4E64-47DD-95FB-A8FB68B840...
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Wednesday, 5 October 2011
5.2 Plenary Answer
5.2 Plenary Answer 04 October 2011 14:16
· If you take a piece of wood that's got a density of 2.4g/cm3 and cut it exactly in half, what will the density of each of the 2 new pieces of wood be?
· 2.4g/cm3!
· You've halved the mass of each block but you've also halved the volume of each block, so the ratio m/V remains contant!
· For example…
· ρbig block = m/V = 240/100 = 2.4g/cm3
· ρsmall block = m/V = 120/50 = 2.4g/cm3
· If you take a piece of wood that's got a density of 2.4g/cm3 and cut it exactly in half, what will the density of each of the 2 new pieces of wood be?
· 2.4g/cm3!
· You've halved the mass of each block but you've also halved the volume of each block, so the ratio m/V remains contant!
· For example…
· ρbig block = m/V = 240/100 = 2.4g/cm3
· ρsmall block = m/V = 120/50 = 2.4g/cm3
5.2
Density formula.ppt Download this file
· 5.2 recall and use the relationship between density, mass and volume:
density = mass / volume ρ = m / V
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