6.19 and 6.20 Plenary answers 01 December 2011 18:08
[cid:image001.png@01CCE7CB.95BA8CB0]
a. Vs/Vp=ns/np Vs/2=80/20 Vs=8V
b. Vs/Vp=ns/np Vs/10=20/100 Vs=2V
c. Vs/Vp=ns/np Vs/240=20/400 Vs=12V
d. Vs/Vp=Ns/Np Vs/4=2000/50 Vs=160V [cid:image002.jpg@01CCE7CB.95BA8CB0]
2. Vs/Vp=ns/np 3/24=ns/480 ns=60turns [cid:image003.jpg@01CCE7CB.95BA8CB0]
a. Iron (Why? Iron is a magnetically soft material - it can be magnetised and lose its magnetism easily. This is necessary in a transformer as the magnetic field needs to change repeatedly)
b. electrical energy in the primary coil => magnetic energy in the core =>electrical energy in the secondary coil
c. dc current produces a steady magnetic field in the core. To induce a current in the secondary coils there must be a changing magnetic field in the core. [cid:image004.jpg@01CCE7CB.95BA8CB0]
a. Step down (because the voltage decreases)
b. Vs/Vp=ns/np 12/240=ns/1000 ns=50turns
c. P = V x I 24 = 12 x I I = 2A
d. Power in secondary = 24W
e. Power in primary = 24W
f. P = V x I 24 = 240 x I I = 0.1A
g. The current would be greater/double Why? Efficiency = Useful Pout/Total Pinx100 50 = 24/Total Pin x 100 Total Pin = 48W P = V x I 48 = 240 x I I = 0.2A
[cid:image001.png@01CCE7CB.95BA8CB0]
a. Vs/Vp=ns/np Vs/2=80/20 Vs=8V
b. Vs/Vp=ns/np Vs/10=20/100 Vs=2V
c. Vs/Vp=ns/np Vs/240=20/400 Vs=12V
d. Vs/Vp=Ns/Np Vs/4=2000/50 Vs=160V [cid:image002.jpg@01CCE7CB.95BA8CB0]
2. Vs/Vp=ns/np 3/24=ns/480 ns=60turns [cid:image003.jpg@01CCE7CB.95BA8CB0]
a. Iron (Why? Iron is a magnetically soft material - it can be magnetised and lose its magnetism easily. This is necessary in a transformer as the magnetic field needs to change repeatedly)
b. electrical energy in the primary coil => magnetic energy in the core =>electrical energy in the secondary coil
c. dc current produces a steady magnetic field in the core. To induce a current in the secondary coils there must be a changing magnetic field in the core. [cid:image004.jpg@01CCE7CB.95BA8CB0]
a. Step down (because the voltage decreases)
b. Vs/Vp=ns/np 12/240=ns/1000 ns=50turns
c. P = V x I 24 = 12 x I I = 2A
d. Power in secondary = 24W
e. Power in primary = 24W
f. P = V x I 24 = 240 x I I = 0.1A
g. The current would be greater/double Why? Efficiency = Useful Pout/Total Pinx100 50 = 24/Total Pin x 100 Total Pin = 48W P = V x I 48 = 240 x I I = 0.2A
No comments:
Post a Comment