5.18 Gay-lussac's law 28 October 2011 11:11
· 5.18 use the relationship between the pressure and Kelvin temperature of a fixed mass of gas at constant volume: p1 / T1 = p2 / T2 p1 = Pressure at the beginning [kPa, bar or atm ] T1 = Absolute temperature at the beginning [K] p2 = Pressure at the end [kPa, bar or atm] T2 = Absolute temperature at the end [K] (Note: the units of temperature must be Kelvin, not oC! The units of pressure can be any, as long as the same at the beginning and the end) 5.18 Ideal graph and conclusion 09 November 2011 15:15 [cid:image001.png@01CCA052.93FBD8E0]
[cid:image002.png@01CCA052.93FBD8E0]
· 5.18 use the relationship between the pressure and Kelvin temperature of a fixed mass of gas at constant volume: p1 / T1 = p2 / T2 p1 = Pressure at the beginning [kPa, bar or atm ] T1 = Absolute temperature at the beginning [K] p2 = Pressure at the end [kPa, bar or atm] T2 = Absolute temperature at the end [K] (Note: the units of temperature must be Kelvin, not oC! The units of pressure can be any, as long as the same at the beginning and the end) 5.18 Ideal graph and conclusion 09 November 2011 15:15 [cid:image001.png@01CCA052.93FBD8E0]
[cid:image002.png@01CCA052.93FBD8E0]
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